Pretty much trade. You give vendor money or currency in return they give you the thing you paid for.
<em>Step #1: </em>
Make sure the equation is in the form of [ Ax² + Bx + C = 0 ].
Yours is already in that form.
A = 1
B = 2
C = -2
<em>Step #2:</em>
The 'discriminant' for that equation is [ B² - 4 A C ].
That's all there is to it, but it can tell you a lot about the roots of the equation.
-- If the discriminant is zero, then the left side of the equation is a perfect square,
and both roots are equal.
-- If the discriminant is greater than zero, the the roots are real and not equal.
-- If the discriminant is less than zero, then the roots are complex numbers.
The discriminant of your equation is [ B² - 4 A C ] = 2² - 4(1)(-2) = 4 + 8 = 12
Your equation has two real, unequal roots.
Answer:
D. 3x²
General Formulas and Concepts:
<u>Algebra II</u>
- If you raise e to the natural log, they cancel out and vice versa
<u>Calculus</u>
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Step-by-step explanation:
<u>Step 1: Define</u>
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<u>Step 2: Rewrite</u>
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<u>Step 3: Take Derivative</u>
- Basic Power Rule: f'(x) = 3x³⁻¹
- Simplify: f'(x) = 3x²
We're minimizing
subject to
. Using Lagrange multipliers, we have the Lagrangian
with partial derivatives
Set each partial derivative equal to 0:
Subtracting the second equation from the first, we find
Similarly, we can determine that
and
by taking any two of the first three equations. So if
determines a critical point, then
So the smallest value for the sum of squares is
when
.
Answer:
2/3 cup
Step-by-step explanation:
first you need to convert the fractions so that they have the same denominator (1/3 turns into 2/6)
then you just add up the numerators (2+2=4..... 4/6)
you can stop there or you can simplify it (4/6 turns into 2/3)