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2 years ago

Exhibit a population of ten integers having mean=20 and variance=4

Mathematics

1 answer:

Alla [95]2 years ago

8 0

exhibit population for ten integers is 15,19,19,20,20,20,21,22,22,22 mean is 20 variance is 4

Step-by-step explanation:

Mean is helps in finding the mid point of the data.
Variance is the variability of data it was here.
In order to get the data straight the combination of 4 was required.
4 is variance one data set was 19 other had to be 22.
As mean is 20 three means had to be 20.
from mean 20 4 is greater then 20 and 3 is less then 20.
15 being the lowest it compensated the variance to 4.
Mathematically there are many ways to do this using function.
This is to be found out at a traditional method.
Reducing or increase the number as it was integers.

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In a string of 12 Christmas tree light bulbs, 3 are defective. The bulbs are selected at random and tested, one at a time, until

Juliette [100K]

Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

In this problem:

There are 12 bulbs, hence N = 12.

3 are defective, hence k = 3.

The third defective bulb is the fifth bulb if:

Two of the first 4 bulbs are defective, which is P(X = 2) when n = 4.

The fifth is defective, with probability of 1/8, as of the eight remaining bulbs, one will be defective.

Hence:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$P(X = 2) = h(2,12,4,3) = \frac{C_{3,2}C_{9,1}}{C_{12,4}} = 0.2182$

0.2182 x 1/8 = 0.0273.

0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

8 0

1 year ago

1,2,4,7,11,16,22, ___,____<br> What is the rule?

Paha777 [63]

Find rates of change until you find a constant.

dy/dx=1,2,3,4,5,6

d2y/dx2=1,1,1,1,1

So the acceleration, d2y/d2x, is constant. This means that this is a quadratic sequence of the form a(n)=an^2+bn+c. So we can set up a system of equations to solve for the values of a,b, and c. Using the first three points, (1,1), (2,2), and (3,4) we have:

9a+3b+c=4, 4a+2b+c=2, and a+b+c=1 getting the differences...

5a+b=2 and 3a+b=1 and getting this difference...

2a=1, so a=1/2 making 5a+b=2 become:

2.5+b=2, so b=-1/2, making a+b+c=1 become:

1/2-1/2+c=1, so c=1 so the rule is:

a(n)=0.5x^2-0.5x+1 or if you prefer to not have decimals

a(n)=(x^2-x+2)/2

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2 years ago

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I don’t know!!!!help please

Bumek [7]

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2 years ago

A retail store sells two types of shoes, sneakers and sandals. The store owner pays $8 for the sneakers and $14 for the sandals.

soldier1979 [14.2K]

Answer:

134 sneakers and 66 sandals

Step-by-step explanation:

Sneakers= x, sandals= y

Profit rate:

sneakers: (10-2)/8= 25%
sandals: (17-14)/14= 21.4%

Sneakers are more profitable, so it should be maximized.

Cost:

8x+14y≤2000

x+y≤200

if we assume the maximum of 200 shoes stocked, then:

x= 200-y

8(200-y)+14y ≤ 2000

1600 - 8y +14y ≤ 2000

6y≤400

y≤66 and x=134 is the best option

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2 years ago

Justin had 44 dollars before spending n dollars on jeans. How much money remains

Svet_ta [14]

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