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1 year ago

Ok here you go theyhatemeforlif3

Mathematics

1 answer:

Juliette [100K]1 year ago

5 0

Answer:

ok im not him but can you give me brainliest

Step-by-step explanation:

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Let A be a set of numbers.

LUCKY_DIMON [66]

Answer:

a. closed under addition and multiplication

b. not closed under addition but closed under multiplication.

c. not closed under addition and multiplication

d. closed under addition and multiplication

e. not closed under addition but closed under multiplication

Step-by-step explanation:

Let A be a set of all integers divisible by 5.

Let $x,y$ ∈A such that $x=5m\,,\,y=5n$

Find $x+y,xy$

$x+y=5m+5n=5(m+n)$

So, $x+y$ is divisible by 5.

$xy=(5m)(5n)=25mn=5(5mn)$

So,

$xy$ is divisible by 5.

Therefore, A is closed under addition and multiplication.

Let A = { 2n +1 | n ∈ Z}

Let $x,y$ ∈A such that $x=2m+1\,,\,y=2n+1$ where m, n ∈ Z.

Find $x+y,xy$

$x+y=2m+1+2n+1=2m+2n+2=2(m+n+1)$

So,

$x+y$ ∉ A

$xy=(2m+1)(2n+1)=4mn+2m+2n+1=2(2mn+m+n)+1$

So,

$xy$ ∈ A

Therefore, A is not closed under addition but A is closed under multiplication.

$Let A=\{2,5,8,11,14,...\}$

Let $x=2,y=5$ but $x+y=2+5=7$ ∉A

Also,

$xy=2(5)=10$ ∉A

Therefore, A is not closed under addition and multiplication.

Let A = { 17n: n∈Z}

Let $x,y$ ∈ A such that $x=17n,y=17m$

Find x + y and xy

$x+y=17n+17m=17(n+m)$

$xy=(17m)(17n)=289mn=17(17mn)$

So,

$x+y,xy$ ∈ A

Therefore, A is closed under addition and multiplication.

Let A be the set of nonzero real numbers.

Let $x,y$ ∈ A such that $x=-1,y=1$

Find x + y

$x+y=-1+1=0$

So,

$x+y$ ∈ A

Also, if x and y are two nonzero real numbers then xy is also a non-zero real number.

Therefore, A is not closed under addition but A is closed under multiplication.

4 0

2 years ago

John's grade increased from a 77 to an 85. What is the approximate percent increase of John's grade

pentagon [3]

Answer:

10.4 hope this help ;) 77 x 10.4

Step-by-step explanation

turn the 10.4 into .10 then multiply like this

77 x .10 =7.7

77+ 7.7 = 84.7

7 0

2 years ago

Read 2 more answers

Simplify and show step by step 30 POINTS!

PIT_PIT [208]

Step-by-step explanation:

the explanation is in the diagram above

4 0

2 years ago

To the nearest tenth, find the perimeter of ABC with vertices A(-1,4), B(-2,1) and C(2,1). show your work

liubo4ka [24]

we have to firstly apply the distance formula to find the length of sides of the triangle

distance formula = $\sqrt{(x_{2} -x_{1})^2 +(y_{2}- y_{1})^2}$

So length AB = $\sqrt{(-2-(-1))^2+(1-4)^2}= \sqrt{1 +9}=\sqrt{10}$

BC= $\sqrt{(2-(-2))^2+(1-1)^2}= \sqrt{16+0}=4$

AC = $\sqrt{(2-(-1))^2+ (1-4)^2}= \sqrt{9+9}=\sqrt{18}=3\sqrt{2}$

Now perimeter = AB+BC+AC = $\sqrt{10}+4+3\sqrt{2}$

Plug in calculator

perimeter= 11.4 units

7 0

2 years ago

AysviL [449]

Since CAB is similar to EFD, then the length of DE would be as follows: 28.

6 0

2 years ago