A rubber ball is bounced from a height of 9 meters and bounces continuously .Each successive bounce reaches a height that is a t
hrid of the previous height. If the ball continues to bounce in this way, what height will the ball reach during the sixth bounce?
2 answers:
Answer:
1/81 meters
Step-by-step explanation:
Since it reaches a height of 1/3 the previous height after each bounce, we can set up an equation for "y", the balls height, after x bounces:
Therefore, to find the ball's height after 6 bounces we just plug-in 6 for x in the equation above to get 1/81.
Hope this helps :)
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Answer:
en que te ayudo
Step-by-step explanation:
TIENES TAREA
I=PRT/100
1. Make R (rate) subject
R/100= I/PT
2. Substitute and calculate
r/100= i/pt
r/100= 40/400 × 1
(<em>4</em><em>0</em><em> </em><em>i</em><em>s</em><em> </em>from 440-400.<em>T</em><em>h</em><em>e</em><em> </em><em>i</em><em>n</em><em>t</em><em>e</em><em>r</em><em>e</em><em>s</em><em>t</em>)
r/100= 0.1
r/100×100= 0.1×100
r=10% (interest rate per year)
To confirm
I=PRT
I= 400×10/100×1
I= $40 (Interest)
6 I believe if this is wrong sorry