An architect plans to make a drawing of the room of a house. The segment LM represents the ceiling of the room. He wants to construct a line passing through Q and perpendicular to side LM to represent a wall of the room. He uses a straightedge and compass to complete some steps of the construction, as shown below:
Applying the linear pair theorem, the measure of angle TSV in the image given is: 86°.
<h3>How to Apply the Linear Pair Theorem?</h3>
Given the following angles in the image above:
Measure angle RSU = (17x - 3)°,
Measure angle UST = (6x – 1)°
To find the measure of angle TSV, we need to find the value of x in the given expressions as shown below:
m∠RSU + m∠UST = 180 degrees (linear pair]
Substitute the values
17x - 3 + 6x - 1 = 180
Solve for x
23x - 4 = 180
23x = 180 + 4
23x = 184
x = 8
m∠TSV = 180 - 2(m∠UST) [Linear Pair Theorem]
m∠TSV = 180 - 2(6x - 1)
Plug in the value of x
m∠TSV = 180 - 2(6(8) - 1)
m∠TSV = 86°
Therefore, applying the linear pair theorem, the measure of angle TSV in the image given is: 86°.
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Answer:
trigonometry
Step-by-step explanation:
hope this helps lovely
Answer:
Step-by-step explanation:
Area of the figure = area of the down triangle + area of trapezium + area of the upper triangle
Down triangle:
Base b = 8 in
Height = 6 in
= 24 in²
Trapezium:
bases a = 4 in & b = 6 in
Height h = 5 in
= 25 in²
Area of the upper triangle:
Base b = 6 in
Height = (8 - 5) = 3 in
= 9 in²
Area of the figure = 24 + 25 + 9 = 58 in²