Draw the image of the following triangle after a dilation centered at the origin with a scale factor of 2.

Mathematics

1 answer:

Natasha_Volkova [10]2 years ago

5 0

I really don’t know but I guess 2

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Find the output (y) of the function y=6x+4 if the input (x) is 2

Dmitry_Shevchenko [17]

Answer:

f(2) = 16

y = 16

Step-by-step explanation:

Step 1: Write out function

y = 6x + 4

Step 2: Define variable for problem

x = 2

Step 3: Plug into function f(x)

f(2) = 6(2) + 4

f(2) = 12 + 4

f(2) = 16

Step 4: Change f(2) to y

y = 16

6 0

2 years ago

(1 ÷ x- 1)+(2÷ x+2)=(3÷2) solve and check for extraneous solutions

Sliva [168]

$\frac{1}{x-1}+ \frac{2}{x+2}= \frac{3}{2}$
$\frac{1(x+2)}{(x-1)(x+2)}+ \frac{2(x-1)}{(x+2)(x-1)}= \frac{3(x-1)(x+2)}{2}$
$\frac{x+2+2(x-1)}{(x-1)(x+2)}= \frac{3(x-1)(x+2)}{2}$
$\frac{x+2+2x-1}{(x-1)(x+2)}= \frac{3(x-1)(x+2)}{2}$
$\frac{3x+1}{(x-1)(x+2)}= \frac{3(x^2+x-2)}{2}$
$\frac{}{(x-1)(x+2)}= \frac{3x^2+3x-6)}{2}$
$\frac{3x+1}{(x^2+x-2)}= \frac{3x^2+3x-6)}{2}$
$\frac{2(3x+1)}{2(x^2+x-2)}= \frac{3x^2+3x-6)(x^2+x-2)}{2(x^2+x-2)}$
$\frac{2(3x+1)}{2(x^2+x-2)}-\frac{3x^2+3x-6)(x^2+x-2)}{2(x^2+x-2)}=0$
$\frac{2(3x+1)-3x^2+3x-6}{2(x^2+x-2)}=0$

this will be continued

5 0

2 years ago

Which expression is equivalent to (7x−5)−(3x−2)?

Alchen [17]

Answer:

D. 4x-3

Step-by-step explanation:

First you subtract the 7x and 3x to get 4x.

Then you subtract the -5 and the -2 to get -3

Therfore, your answer is D

4 0

2 years ago