Answer:
32.6 %
Explanation:
Given data
- Mass of sucrose (solute): 22.8 grams
- Mass of water (solvent): 47.1 grams
Step 1: Calculate the mass of the solution
The mass of the solution is equal to the sum of the mass of the solute and the mass of the solvent.
m(solution) = m(solute) + m(solvent)
m(solution) = 22.8 g + 47.1 g
m(solution) = 69.9 g
Step 2: Calculate the percent-by-mass of sucrose in the solution
We will use the following expression.
Question 5)
1 Hour: 100g
40 Minutes: 50g
20 Minutes: 25g
0 Minutes: 12.5g
Question 6)
160 Days: 80ou
120 Days: 40ou
80 Days: 20ou
40 Days: 10ou
0 Days: 5ou
Every period of time, the radioactive isotopes halve in numbers as they emit radiation.
I think you now know the gist. Try doing the rest yourself.
Good luck.
Answer:
a. 2954g of FeS
b. 1143g of FeS
Explanation:
Based on the reaction:
8 Fe + S₈ → 8 FeS
<em>8 moles of Fe reacts with 1 mole of S₈ to produce 8 moles of FeS</em>
<em />
a. 4.2mol sulfur produce:
4.2mol S₈ × ( 8 mol FeS / 1 mol S₈) = <em>33.6mol FeS</em>. As molar mass of FeS is 87.92g/mol, mass is:
33.6mol FeS × ( 87.92g / 1 mol FeS) = <em>2954g of FeS</em>
<em />
b. 13mol Fe produce:
13mol Fe × ( 8 mol FeS / 8 mol Fe) = <em>13mol FeS</em>. In mass:
13 mol FeS × ( 87.92g / 1 mol FeS) = <em>1143g of FeS</em>
Metals, for example Cesium and Francium
