Answer:
both kinds of tickets are $5 each
Step-by-step explanation:
Let s and c represent the dollar costs of a senior ticket and child ticket, respectively. The problem statement describes two relationships:
12s + 5c = 85 . . . . . revenue from the first day of sales
6s + 9c = 75 . . . . . . revenue from the second day of sales
Double the second equation and subtract the first to eliminate the s variable.
2(6s +9c) -(12s +5c) = 2(75) -(85)
13c = 65 . . . . . simplify
65/13 = c = 5 . . . . . divide by the coefficient of c
Substitute this value into either equation. Let's use the second one.
6s + 9·5 = 75
6s = 30 . . . . . . . subtract 45
30/6 = s = 5 . . . divide by the coefficient of s
The price of a senior ticket is $5; the price of a child ticket is $5.
The answers would be 49,51,and53!
H + 2 divided by 4
Please mark as brainliest!
<h2>A. $123.51</h2><h2 />
: $24.48 per year + price * 0.85
: $36.83 per year + price * 0.75
Substitute each value into both equations as price.
A:
129.4635
129.4625
B:
98.158
101.84
C:
145.2055
143.3625
D:
155.703
152.615
A is the lowest value where the second value is lower than the first.
Mot enough information given.
The rule might be
-- add 6
or
-- double and add 8
or
-- square
or
-- multiply by -2 .
We need one more term to determine what the rule is for calculating the next term from the previous one.
The
