The correct representations of the given inequality are
–6x + 15 < 10 – 5x
and
A number line with an <u>open circle</u> at 5 and a bold line that starts at 5 and is <u>pointing to the right</u>. The correct options are the third and fourth options
<h3>Solving inequality</h3>
From the question, we are to solve the inequality
The given inequality is
–3(2x – 5) < 5(2 – x)
First, clear the brackets
–6x + 15 < 10 – 5x
NOTE: This is one of the correct representations of the inequality
Collect like terms
-6x + 5x < 10 - 15
-x < -5
Divide both sides by -1 and flip the sign
x > 5
Representing this on a number line, we get a number line with an <u>open circle</u> at 5 and a bold line that starts at 5 and is pointing to the right.
Hence, the correct representations of the given inequality are
–6x + 15 < 10 – 5x
and
A number line with an <u>open circle</u> at 5 and a bold line that starts at 5 and is <u>pointing to the right</u>. The correct options are the third and fourth options
Learn more on Inequalities here: brainly.com/question/246993
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Answer:
64
Step-by-step explanation:
Note that each new term of this geometric sequence is 2x the previous term.
If the sequence starts off as 2, 4, 8, 16, 32 ... , then the next term is 2(32) = 64.
(Where did the '48' come from?)
Okay, so this is just a basic multiplication problem. first, we need to divide to figure out how much the trout population grows after 1 year. If it doubles in 4 years, then it will rise by a quarter each single year. So to put that in terms of fractions, then for every year, the equation would be 250x1/4. So then we do the equation, coming up with 62.5. This means that the population rises roughly 63 fish a year. So after 1 year, you will have roughly 313 fish. (312.5 to be exact). Then to get that by ten years, we can just multiply the number that we got for one year by ten. 62.5x10=625. So then we add the 250 original trout, and 250+625=875. So after 10 years, there will be 875 trout.
Answer:
7. C
8. B
9. B
Step-by-step explanation:
7: A proper fraction is a fraction where the numerator is greater than the denominator. Choice <em>a</em> is a decimal, not a fraction. Choice <em>b</em> is a fraction, but its numerator is equal to its denominator. Choice <em>d</em> is also a fraction, but its denominator is greater than its numerator. Choice <em>c</em> is correct, because it is a fraction where its numerator is greater than its denominator.
8. A decimal fraction has denominators like 10, 100, 1000, as so on. It is a fraction.
9. A fraction is equal to the numerator divided by the denominator. When the numerator is equal to the denominator, the value of the numerator divided by the denominator is 1.
I don't understand your language sorry
