Answer:
440 hours
Step-by-step explanation:
In this case the aircraft has completed one cycle of service in the first 454 hours of service. Then making the difference between the hours of service and the hours of the first cycle we have:
Hours of the second cycle= Total time in service- time Airworthiness Directive
=468-454=14
Then we have 14 hours of service and need to accumulate the rest to complete 454. It is
454-14=440
Then we need to accumulate 440 hours additional to complete the Airworthiness Directive .
100
6738 —> 7000
5903 —> 6000
7000 - 6000 = 1000
i. 171
ii. 162
iii. 297
Solution,
n(U)= 630
n(I)= 333
n(T)= 168
i. Let n(I intersection T ) be X
<h3>ii.
n(only I)= n(I) - n(I intersection T)</h3><h3>
= 333 - 171</h3><h3>
= 162</h3>
<h3>
iii. n ( only T)= n( T) - n( I intersection T)</h3><h3>
= 468 - 171</h3><h3>
= 297</h3>
<h3>
Venn- diagram is shown in the attached picture.</h3>
Hope this helps...
Good luck on your assignment...
1 people eat 3/8 pound of potato salad lets reoresent it:
x=3/8
Lets say n is the value of how many people ate with 7 people
7x=n
now substitute
7x=n
7(3/8)=n
21/8=n
n=2 5/8