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1 year ago

7

Members of the math club held a bake sale to raise money. Cupcakes and cookies were sold.

1 answer:

Mrac [35]1 year ago

4 0

Answer:

Cupcake

Step-by-step explanation:

Because the sale price is bigger

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Help NEEDED!!!! plzzzzzz.....

julsineya [31]

Sin30= opposite/hypotenuse
sin30= AC/10
AC= 4.5cm
Tan25= opposite/adjacent
Tan25= 4.5/ CD
CD= 10.7

7 0

2 years ago

How many solutions does this equation have?

Natalija [7]

Answer:

1 answer

Step-by-step explanation:

when the terms are collected

$4k = 0$

$k = 0$

5 0

6 months ago

Three same-sized cubes are attached to the top of a rectangular prism as shown below

-Dominant- [34]

Answer:

458 cm²

Step-by-step explanation:

5 × 5 × 2 + 5 × 18 × 4 = 50 + 360 = 410

2 × 2 × 4 × 3 = 48

410 + 48 = 458

6 0

2 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

astra-53 [7]

Answer:

$3\pi \rightarrow y=2\cos \dfrac{2x}{3}\\ \\\dfrac{2\pi }{3}\rightarrow y=6\sin 3x\\ \\\dfrac{\pi }{3}\rightarrow y=-3\tan 3x\\ \\10\pi \rightarrow y=-\dfrac{2}{3}\sec \dfrac{x}{5}$

Step-by-step explanation:

The period of the functions $y=a\cos(bx+c)$ , $y=a\sin(bx+c)$ , $y=a\sec (bx+c)$ or $y=a\csc(bx+c)$ can be calculated as

$T=\dfrac{2\pi}{b}$

The period of the functions $y=a\tan(bx+c)$ or $y=a\cot(bx+c)$ can be calculated as

$T=\dfrac{\pi}{b}$

A. The period of the function $y=-3\tan 3x$ is

$T=\dfrac{\pi}{3}$

B. The period of the function $y=6\sin 3x$ is

$T=\dfrac{2\pi}{3}$

C. The period of the function $y=-4\cot \dfrac{x}{4}$ is

$T=\dfrac{\pi}{\frac{1}{4}}=4\pi$

D. The period of the function $y=2\cos \dfrac{2x}{3}$ is

$T=\dfrac{2\pi}{\frac{2}{3}}=3\pi$

E. The period of the function $y=-\dfrac{2}{3}\sec \dfrac{x}{5}$ is

$T=\dfrac{2\pi}{\frac{1}{5}}=10\pi$

5 0

2 years ago

Which of the following is an example of perpendicular lines

lozanna [386]

Answer:

B...........................................................

7 0

1 year ago

Read 2 more answers