Actual yield/Theoretical yield *100= Percentage yield. So Actual yield = Percentage yield*Theoretical yield.
Therefore actual yield= 90/100 * 1.09g = 0.98g
Actual yield: 0.98 g
First you need to know how many moles you would get from 165 g of carbon dioxide.
Carbon = 12
Oxygen 2 = 16 x 2 = 32
Total: 32 + 12 = 44
- Use proportions
1 mol CO2 x 1 mol CO2 44 g
---------------- = ---------- or ----------------- = ----------
44 g 165 x 165 g
165/44 = 3.75 moles CO2
- Last step is to multiply the amount of moles by Avagadros number, 6.02 x 10^23
3.75 x 6.02 x 10^23 = 2.25 x 10^24 molecules
- Keep in mind if your answer can be a little different than mind if you either round or keep the same numbers. I hope this Really Helps ! c:
Answer:
D. Na2O
Because we already know that sodium oxide is a binary ionic compound because it contains one metal cation and one non-metal anion.
The atom has 7 neutrons and 8 protons....
because the positively charged particles are the protons ...and 8 is also the atomic number ...so number of neutrons can be calculated by subtracting atomic number from the mass number...which gives us the neutrons 7 ...
Answer:
CuNO3
Explanation:
In order to calculate the empirical formula in this question;
Cu = 50.61% = 50.61g
N = 11.16% = 11.16g
O = 38.23% = 38.23g
Next, we convert each gram unit to moles by dividing by their respective molar mass (Where; Cu = 63.55, N = 14, O = 16)
Cu = 50.61 ÷ 63.55 = 0.796mol
N = 11.16 ÷ 14 = 0.797mol
O = 38.23 ÷ 16 = 2.389mol
Next, we divide each mole value by the smallest (0.796)
Cu = 0.796mol ÷ 0.796 = 1
N = 0.797mol ÷ 0.796 = 1.001
O = 2.389mol ÷ 0.796 = 3.001
Approximately, the simple whole number ratio between Cu, N and O is 1:1:3, hence, the empirical formula is CuNO3.