The recursive sequence that would produce the sequence 8,-35,137,… is T(n + 1) = -3 - 4T(n) where T(1) = 8
<h3>How to determine the recursive sequence that would produce the sequence?</h3>
The sequence is given as:
8,-35,137,…
From the above sequence, we can see that:
The next term is the product of the current term and -4 added to -3
i.e.
Next term = -3 + Current term * -4
So, we have:
T(n + 1) = -3 + T(n) * -4
Rewrite as:
T(n + 1) = -3 - 4T(n)
Hence, the recursive sequence that would produce the sequence 8,-35,137,… is T(n + 1) = -3 - 4T(n) where T(1) = 8
Read more about recursive sequence at
brainly.com/question/1275192
#SPJ1
Answer:
3456
Step-by-step explanation:
Answer:The mode if 5, because 5 occurs 8 times, which is more than any other numbers occurring more than once. The median is 6, and this is because when you line up the numbers in order and cross them off to find the middle number, it is 6. I rounded to the mean to about 6.4. I got this by adding all of the numbers up, or by doing 12 + 40 +18 +7, etc, and got the total of 165. Because there is a total of 26 data points, I divided those numbers and got 6.3461, which ends up rounding to 6.4.
Step-by-step explanation:
Answer:
Adding 7 to both sides of the equal sign
Step-by-step explanation:
Answer:
15
Step-by-step explanation:
The product of the prime factors of 3375 are
3375 = 3³ × 5³, then
![\sqrt[3]{3375}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3375%7D)
= ![\sqrt[3]{3^3(5^3)}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%5E3%285%5E3%29%7D)
= ![\sqrt[3]{3^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%5E3%7D)
× ![\sqrt[3]{5^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%5E3%7D)
= 3 × 5
= 15
