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1 year ago

Translate this phrase into an algebraic expression.

Mathematics

1 answer:

stira [4]1 year ago

3 0

74 - 2m

"decreased by" means subtracted by and twice of Malik's height would be 2 multiplied by his height.

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Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is μd =

swat32

Answer:

Test statistic, $t_{s} = -0.603$ (to 3 dp)

Step-by-step explanation:

Deviation, d = x -y

Sample mean for the deviation

$\bar{d} = \frac{\sum x-y}{n}$

$\bar{d} = \frac{(28-6) + (31-27)+(20-26)+(25-25)+(28-29)+(27-32)+(33-33)+(35-34)}{8} \\\bar{d} = -0.625$

Standard deviation: $SD = \sqrt{\frac{\sum d^{2} - n \bar{d}^2}{n-1} }$

$\sum d^{2} = (28-26)^2 + (31-27)^2 +(20-26)^2 +(25-25)^2 +(28-29)^2 +(27-32)^2 +(33-33)^2 +(35-34)^2\\\sum d^{2} = 63$

$SD = \sqrt{\frac{63 - 8 * (-0.625)^2}{8-1} }$

SD =2.93

Under the null hypothesis, the formula for the test statistics will be given by:

$t_{s} = \frac{ \bar{d}}{s_{d}/\sqrt{n} } \\t_{s} = \frac{- 0.625}{2.93/\sqrt{8} }$

$t_{s} = -0.6033$

6 0

2 years ago

I dont understand this question. Also if anyone is on geometry byu part two let me know and we can work together !

damaskus [11]

Answer:

Area of circle R = 75π un² or ≈235.5 un²

Step-by-step explanation:

The problem says that m∠TRS = 120º. The total number of degrees in a circle is 360º. 120º is a third of 360º. Therefore, we can prove that the shaded sector is a third of the circle.

The problem then says that the area of the shaded sector is 25π and we have to calculate the area of the entire circle. Since we already know that the shaded sector is a third of the circle, we can simply multiply 25π by 3 in order to calculate the area of t he entire circle.

25π × 3 = 75π.

Area of circle R = 75π un² or ≈235.5 un²

4 0

2 years ago

given sin A =3/-/34 and that angle S is in quadrant 1, find the exact value of tan A in simplest radical form using a ration

Vedmedyk [2.9K]

Answer:

$\tan(A) = \frac{3}{5}$

Step-by-step explanation:

Given

$\sin(A) = \frac{3}{\sqrt {34}}$

$0 \le A \le 90$ --- First Quadrant

Required

Find tan(A)

The sin of an angle is:

$\tan(A) = \frac{Opposite}{Hypotenuse}$

and

$\sin(A) = \frac{3}{\sqrt {34}}$

By comparison:

$Opposite = 3$

$Hypotenuse = \sqrt{34$

So, the Adjacent is:

$Hypotenuse^2 = Adjacent^2 + Opposite^2$

$(\sqrt{34})^2 = Adjacent^2 + 3^2$

$34 = Adjacent^2 + 9$

Collect like terms

$Adjacent^2 =34 - 9$

$Adjacent^2 =25$

Take square roots

$Adjacent =\sqrt{25$

$Adjacent =5$

The tangent of an angle is:

$\tan(A) = \frac{Opposite}{Adjacent}$

This gives:

$\tan(A) = \frac{3}{5}$

8 0

2 years ago

A 12 ounce bottle of cleaner cost $3.74 a 16 ounce bottle of cleaner cost $5.34 which bottle would be the best spot which cost l

Valentin [98]

Answer:

12 ounce bottle

Step-by-step explanation:

12 x 3 = 36

16 x 5 = 80

So, that means the 12 ounce bottle is cheaper. :)

5 0

3 years ago

Solve for x. please show work

Mazyrski [523]

Those 2 angles makes up corresponding angles in parallel lines. Which means, both two angles equal to each other because this is a rule that exists when both of the lines are parallel to each other which is indicated with red arrows in the photo.
75 = 11x - 2
75 + 2 = 11x
77 = 11x
X = 77 / 11
X = 7
The answer is 7.

3 0

2 years ago