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1 year ago

Fh

Mathematics

1 answer:

scZoUnD [109]1 year ago

4 0

Answer:

ok so just get the v12{{9-))0} and =14

Step-by-step explanation:

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Factor the expression using the GCF. 18-12

rodikova [14]

Answer:

6(3-2)

Step-by-step explanation:

Find the GCF of both numbers. The GCF is 6. Write it as 6( - )

Then, divide both numbers by 6. 18 divided by 6 is 3 and 12 divided by 6 is 2. Fill in the blanks with 3 and 2. A=6(3-2)

7 0

2 years ago

2x-y=4 and y=-2x+8.<br><br> Can anyone help me solve

Komok [63]

Answer:

The correct answer is x = 3 and y = 2.

Step-by-step explanation:

There are many ways to solve systems of equations like this, but I'm going to use substitution. This means taking the value of y given by the second equation and plugging it into the first equation. This is modeled below:

2x - y = 4

2x - (-2x+8) = 4

Now, we can simplify the left side of the equation.

2x + 2x - 8 = 4

4x - 8 = 4

We should add 8 to both sides as the next step.

4x = 12

Now we can divide by 4.

x = 3

To solve for y, we can substitute this value found for x back into either one of our original equations.

y = -2x + 8

y = (-2*3) + 8

y = -6 + 8

y = 2

Therefore, the correct answer is x = 3 and y = 2.

Hope this helps!

5 0

2 years ago

Read 2 more answers

Aaron wants to mulch his garden. His garden is x^2+18x+81 ft^2 One bag of mulch covers x^2-81 ft^2 . Divide the expressions and

blsea [12.9K]

Answer:

Step-by-step explanation:

Given

Garden: $x^2+18x+81$

One Bag: $x^2 - 81$

Requires

Determine the number of bags to cover the whole garden

This is calculated as thus;

$Bags = \frac{x^2+18x+81}{x^2 - 81}$

Expand the numerator

$Bags = \frac{x^2+9x+9x+81}{x^2 - 81}$

$Bags = \frac{x(x+9)+9(x+9)}{x^2 - 81}$

$Bags = \frac{(x+9)(x+9)}{x^2 - 81}$

Express 81 as 9²

$Bags = \frac{(x+9)(x+9)}{x^2 - 9\²}$

Evaluate as difference of two squares

$Bags = \frac{(x+9)(x+9)}{(x - 9)(x+9)}$

$Bags = \frac{(x+9)}{(x - 9)}$

Hence, the number of bags is $Bags = \frac{(x+9)}{(x - 9)}$

3 0

2 years ago

Can anyone solve this

ludmilkaskok [199]

Answer: it wont let me see the picture so i cant help you

Step-by-step explanation:

3 0

2 years ago

Function f is represented by the equation shown.

aliya0001 [1]

Answer:

$\boxed{\text{A. The y-intercept of function f is greater than the y-intercept of function g}}$

Step-by-step explanation:

A. y-Intercept of ƒ(x)

ƒ(x) = x² - 4x + 3

f(0) = 0² - 4(0) + 3 = 0 – 0 + 3 = 3

The y-intercept of ƒ(x) is (0, 3).

If g(x) opens downwards and has a maximum at y = 3, it's y-intercept is less than (0, 3).

Statement A is TRUE.

B. y-Intercept of g(x)

Statement B is FALSE.

C. Minimum of ƒ(x)

ƒ(x) = x² - 4x + 3

a = 1; b = -4; c = 3

The vertex form of a parabola is

y = a(x - h)² + k

where (h, k) is the vertex of the parabola.

h = -b/(2a) and k = f(h)

h = -b/2a = -(-4)/(2×1 = 2

k = f(2) = 2² - 4×2 + 3 =4 – 8 +3 = -1

The minimum of ƒ(x) is -1. The minimum of ƒ(x) is at (2, -1).

Statement C is FALSE.

D. Minimum of g(x)

g(x) is a downward-opening parabola. It has no minimum.

Statement D is FALSE

4 0

2 years ago