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1 year ago

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8. In an inelastic collision kinetic energy is not conserved.

1 answer:

larisa [96]1 year ago

5 0

Answer:

Pls give full question pls

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Which substance(s) will sink if placed in a fluid that has a density of 1.19 g/ml? (List all)

olga2289 [7]

Answer:

Corn Syrup

Explanation:

7 0

2 years ago

Write the difference between convert and<br>Concave minores

TEA [102]

A concave mirror is opaque whereas a concave lens is transparent. ... Difference between concave mirror and concave lens is A concave mirror is opaque whereas a concave lens is transparent. A concave mirror causes reflection of light whereas a concave lens causes refraction of light.

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2 years ago

While at the county fair, you decide to ride the Ferris wheel. Having eaten too many candy apples and elephant ears, you find th

Dovator [93]

Answer:

Explanation:

From the given information:

radius = 15 m

Time T = 23 s

a) Speed (v) = $\dfrac{2 \pi r}{T}$

$v = \dfrac{2\times \pi \times 15}{23}$

v = 4.10 m/s

b) The magnitude of the acceleration is:

$a = \dfrac{v^2}{r} \\ \\ a = \dfrac{(4.10)^2}{15}$

a = 1.12 m/s²

c) True weight = mg

Apparent weight = normal force

From the top;

the normal force = upward direction,

weight is downward as well as the acceleration.

true weight - normal force = ma

apparent weight =mg - ma

$\dfrac{apparent \ weight}{true \ weight} = \dfrac{(mg - ma)}{(mg)}$

$=1- \dfrac{1.12}{9.8}$

= 0.886 m/s²

d)

From the bottom;

acceleration is upward, so:

apparent weight - true weight = ma

apparent weight = true weight + ma

$\dfrac{apparent \ weight }{true \ weight} =\dfrac{ mg + ma}{mg}$

$\dfrac{apparent \ weight }{true \ weight} =1+ \dfrac{a}{g} \\ \\ = 1 + \dfrac{1.12}{9.8}$

$= 1 + \dfrac{1.12}{9.8} \\ \\$

= 1.114 m/s²

6 0

2 years ago

Which of the following quantities are unknown?

Novay_Z [31]

Answer:

unknow e and f

Explanation:

In experiments with alpha particles that are obtained by the method of radioactive decay of atoms, some parameters are known

a) Known. The initial velocity is given by the energy of the particles entities by the atomic nuclei

b) Known. The particle charge always 2e, helium core

c) Known. It is set in the given experiment, in general it is selected as zero

d) Known. Placed by the experimenter

e) Unknown. The speed depends on the interactions with the system

f) Unknown. It depends on the interactions with the system, because the position depends on the interactions

g) Known. It is always the value of a helium nucleo

6 0

2 years ago

b) Assume the rod is 0.60 m long and has a mass of 0.50 kg, and the clay blob has a mass of 0.20 kg and moves at an initial velo

SOVA2 [1]

Answer:

The correct answer is "6.96 rad/s".

Explanation:

The given values are:

Length,

L = 0.6 m

Mass,

m₁ = 0.5 kg

m₂ = 0.2 kg

Initial velocity,

V = 8 m/s

Now,

The final angular velocity will be:

⇒ $\omega =\frac{6m_1V}{(4m_1+3m_2)L}$

By substituting the values, we get

⇒ $=\frac{6\times 0.2\times 8}{(4\times 0.2+3\times 0.5)0.6}$

⇒ $=\frac{9.6}{1.38}$

⇒ $=6.96 \ rad/s$

4 0

2 years ago