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2 years ago

Tell which sentence is the best estimate for 200÷26

Mathematics

2 answers:

Neko [114]2 years ago

3 0

Answer:

Estimation is finding a number that is close enough to the right answer. ... 550 + 248: 50+48 is nearly 100 so an estimate is 500+200 +100 = 800.

Rina8888 [55]2 years ago

3 0

D is your answer: because since your looking for which is best for 25 look for which one adds up to 25 so its D hope it helps!

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Jane has a pile of 6 books. Together, the books weigh 4 pounds. If the books aresimilar in weight, about how much does each book

Margaret [11]

Answer:

this is just division

6/4=1/2

each book weighs 1/2

Hope This Helps!!!

5 0

1 year ago

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Write the equation of the line that is parallel to y=4x-1 and passes through the point (4.9)

lutik1710 [3]

9514 1404 393

Answer:

y = 4x -7

Step-by-step explanation:

Rearranging the slope-intercept for equation, we can find the intercept:

y = mx +b

y -mx = b . . . . . subtract mx

We know the slope of the parallel line is the same as that of the given line (m=4), so we only need to find 'b'.

b = 9 -4(4) = -7

The desired equation is ...

y = mx +b

y = 4x -7

8 0

2 years ago

In an upcoming race, the top 3 finishers will be recognized with the same award. There are 12 people entered in the race.

slavikrds [6]

Answer:

220

Step-by-step explanation:

Given,

The total number of people = 12,

Out of which, top 3 finishers will be recognized with the same award,

So, the total possible way = total combination of 3 people out of 12 people

$=^{12}C_3$

$=\frac{12!}{3!(12-3)!}$

$=\frac{12\times 11\times 10\times 9!}{3\times 2\times 9!}$

$=\frac{1320}{6}$

$=220$

Hence, there are 220 ways the top 3 racers can be grouped from the 12 people.

6 0

2 years ago

Line A passes through the points (-8, 5) and (-5, 4). Line B passes through the points (0, 1) and (4, -1). Which of the followin

horrorfan [7]

$\stackrel{\textit{\LARGE Line A}}{(\stackrel{x_1}{-8}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{-5}~,~\stackrel{y_2}{4})} ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{4}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{-5}-\underset{x_1}{(-8)}}} \implies \cfrac{4 -5}{-5 +8}\implies -\cfrac{1}{3} \\\\[-0.35em] ~\dotfill$

$\stackrel{\textit{\LARGE Line B}}{(\stackrel{x_1}{0}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})} ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-1}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{0}}} \implies \cfrac{-1 -1}{4 +0}\implies -\cfrac{1}{2}$

keeping in mind that perpendicular lines have negative reciprocal slopes, and that parallel lines have equal slopes, well, those two slopes above aren't either, so since they're neither, and they're different, that means that lines A and B intersect.

8 0

1 year ago

Please help me find where I should draw the line! Thsm!

Anastasy [175]

Answer:

That should be it if I'm not mistaken. The first one is y= 4+x, and the second one is y= 2x

Step-by-step explanation:

Can I get Brainliest if I'm right?

5 0

1 year ago

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