Answer:
50 deg
Step-by-step explanation:
In an right triangle, the acute angles are complementary. That means their measures have a sum of 90 deg.
m<C + m<B = 90
7x - 20 + 4x = 90
11x = 110
x = 10
m<ACB= 7x - 20
m<ACB = 7(10) - 20
m<ACB = 70 - 20
m<ACB = 50
Answer: m<ACB = 50 deg
Answer: 3
Step-by-step explanation: It is raised to the third power, therefore having a degree of 3.
9514 1404 393
Answer:
- 2nd force: 99.91 lb
- resultant: 213.97 lb
Step-by-step explanation:
In the parallelogram shown, angle B is the supplement of angle DAB:
∠B = 180° -77°37' = 102°23'
Angle ACB is the difference of angles 77°37' and 27°8', so is 50°29'.
Now, we know the angles and one side of triangle ABC. We can use the law of sines to solve for the other two sides.
BC/sin(A) = AB/sin(C)
AD = BC = AB·sin(A)/sin(C) = (169 lb)sin(27°8')/sin(50°29') ≈ 99.91 lb
AC = AB·sin(B)/sin(C) = (169 lb)sin(102°23')/sin(50°29') ≈ 213.97 lb
It equals zero negative plus positive equals zero
Answer:
did it
Step-by-step explanation:
