Answer:
Step-by-step explanation:
If you want to find the equation of line with a given a slope of which goes through the point (-4,5), you can simply use the point-slope formula to find the equation:
---Point-Slope Formula---
where is the slope, and is the given point
So lets use the Point-Slope Formula to find the equation of the line
Plug in , , and (these values are given)
Distribute
Multiply and to get
Add -1 to both sides to isolate y
Combine like terms and to get the answer
So the equation of the line with a slope of which goes through the point (-4,5) is:
which is now in y=mx = b form where the slope is m=-4/5 and the y-intercept is b=1
10 the second power is 10². 10²=10*10=100. 100*18.72=1,872. Hoped I helped. :)
Answer:
x = 60
1) 60
2) 360
3) 160
60 + 360 + 160 = 580
Step-by-step explanation:
1) x
2) 6x
3) x + 100
x + 6x + x + 100 = 580
8x = 580 - 100
x = 480/8
x = 60
Answer:
a
n
=
2
2
n
−
1
Step-by-step explanation:
hope this helps
Note that the 2nd equation can be re-written as y=8x-10.
According to the second equation, y=x^2+12x+30.
Equate these two equations to eliminate y:
8x-10 = x^2+12x+30
Group all terms together on the right side. To do this, add -8x+10 to both sides. Then 0 = x^2 +4x +40. You must now solve this quadratic equation for x, if possible. I found that this equation has NO REAL SOLUTIONS, so we must conclude that the given system of equations has NO REAL SOLUTIONS.
If you have a graphing calculator, please graph 8x-10 and x^2+12x+30 on the same screen. You will see two separate graphs that do NOT intersect. This is another way in which to see / conclude that there is NO REAL SOLUTION to this system of equations.
