For the answer to the question above asking w<span>hich of the following would likely form a heterogeneous mixture?
The answer would be</span> <span>sand and water
other choices like
,baking soda salt and sugar are soluble in water and form homogeneous solution</span>
Answer:
Explanation:
<em>2. A 10 kg bowling ball would require what force to accelerate down an alleyway at a rate of 3m/s² ?</em>
Notice that I completed the question with the garbled and missing values:
<u>Data:</u>
<u />
<u>Physical principles:</u>
- Newton's second law:
<u>Solution:</u>
<em></em>
<em>3. Salty has a car that accelerates at 5 m/s². If the car has a mass of 1000 kg, how much force does the car produce?</em>
Notice that I arranged the typos.
<u />
<u>Data:</u>
<u>Physical principles:</u>
- Newton's second law:
<u>Solution:</u>
<em>4. What is the mass of a falling rock if it produces a force of 147 N?</em>
<u>Data:</u>
<u>Physical principles:</u>
- neglecting air resistance ⇒ a = g: gravitational acceleration: 9.8m/s²
- Newton's second law:
<u>Solution:</u>
- Clear m from Newton's second law
- Substitute with F = 147 N and a = g = 9.8m/s², and compute
<em></em>
<em>5. What is the mass of a truck if it produces a force of 14,000 N while accelerating at a rate of 5 m/s²?</em>
<u>Data:</u>
<u>Physical principles:</u>
- Second Newton's law:
<u>Solution:</u>
- Clear m from Newton's second law
- Substitute with F = 14,000 N and a = 5m/s², and compute
According to this formula:
Q = M*C*ΔT
when we have M ( the mass of water) = 200 g
and C ( specific heat capacity ) of water = 4.18 J/gC
ΔT (the difference in temperature) = Tf - Ti
= 100 - 24
= 76°C
So by substitution:
Q = 200 g * 4.18 J/gC * 76 °C
= 63536 J
∴ the amount of heat which be added and absorbed to raise the temp from 24°C to 100°C is = 63536 J
Answer:
0.010 $.
Explanation:
Hello!
In this case, since 1 troy ounce equals 31.1 grams, we can compute the price of gold per gram first:
Now, we need to compute the grams of copper in 5.17 x10¹⁷ atoms via the Avogadro's number:
Thus, the price is:
Best regards!