Answer:
= 1+2n and 63
Step-by-step explanation:
the question belongs to arithmetic sequence and can be determined by the formula
= a1 + d (n-1)
Let " " represents the number of band members in the nth row
and 'd' represents the common difference.( as stated each row has 2 more band members than the row before it)
therefore, d=2
'a1' represents first row that has three members. So, a1 = 3
->Rule for nth term will be:
= 3 + 2(n-1)
= 3 + 2n -2
= 1+2n
-> In order to find total number of band members '
'
Let 
represent total number in n rows
We'll use the formula, i.e = n/1 (
+ )
where, n is the number of terms, is the first term and is the last term
So,
n=7
= 1 + 2(7)= 15
=> = 7/2 (3 + 15)
= 63
The total number of band members are 63
Consider a homogeneous machine of four linear equations in five unknowns are all multiples of 1 non-0 solution. Objective is to give an explanation for the gadget have an answer for each viable preference of constants on the proper facets of the equations.
Yes, it's miles true.
Consider the machine as Ax = 0. in which A is 4x5 matrix.
From given dim Nul A=1. Since, the rank theorem states that
The dimensions of the column space and the row space of a mxn matrix A are equal. This not unusual size, the rank of matrix A, additionally equals the number of pivot positions in A and satisfies the equation
rank A+ dim NulA = n
dim NulA =n- rank A
Rank A = 5 - dim Nul A
Rank A = 4
Thus, the measurement of dim Col A = rank A = five
And since Col A is a subspace of R^4, Col A = R^4.
So, every vector b in R^4 also in Col A, and Ax = b, has an answer for all b. Hence, the structures have an answer for every viable preference of constants on the right aspects of the equations.
