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1 year ago

Given that

Mathematics

1 answer:

Sophie [7]1 year ago

6 0

Answer:

P = 22

Step-by-step explanation:

We know that:

P = 7x + 20 − 2y
x = 2
y = 6

Work:

P = 7x + 20 − 2y

Substituting the given values

P = 7(2) + 20 − 2(6)

Solving

=> P = 14 + 20 - 12
=> P = 22

Hence, the value of P is 22.

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Simplify: 9(a + b) + 4(3a + 2b) A) 13a 13b B) 21a + 17b C) 21a + 2b D) 38ab

Aneli [31]

The answer is
B) 21a + 17b

8 0

2 years ago

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The area of the circle is 132.7 square centimeters. What is the diameter

VladimirAG [237]

Equating the formula (d is the diameter)

$\pi$ d^2/4 = 132.7
d^2 = 132.7*4/ $\pi$
d = $\sqrt{169.044586}$
d = 13.0017147331
d= 13cm

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2 years ago

Use geometric series to find the fraction of 0.8967898989

Sliva [168]

I'm guessing the repeating part is 89 at the end, so that

$x=0.8967\overline89\implies10^4x=8967.\overline{89}$

Then

$10^4x=8967+\displaystyle89\sum_{i=1}^\infty\frac1{100^i}$

$10^4x=8967+89\left(\dfrac1{1-\frac1{100}}-1\right)$

$10^4x=8967+\dfrac{89}{99}$

$x=\dfrac{8967}{10^4}+\dfrac{89}{99\cdot10^4}$

$x=\dfrac{443911}{495000}$

###

An arguably quicker way without using geometric series:

$10^4x=8967.\overline{89}$

$10^6x=896789.\overline{89}$

$10^6x-10^4x=887822$

$x=\dfrac{887822}{10^6-10^4}=\dfrac{443911}{495000}$

8 0

3 years ago

I need help please, 20 points

valkas [14]

Answer:

the answer is 546 hope this helps :)

Step-by-step explanation:

7 0

2 years ago

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The population of Farmersville can be modeled by the inequality y > 2,000x + 2,100, where x is the number of years since 2010

Kaylis [27]

Answer:

The population can be greater than 6,100 but less than 6,300, and thus, we cannot determine if the population of Farmersville will be greater than 6,300 in 2012.

Step-by-step explanation:

Inequality for the population of Farmsville:

The inequality for the population of Farmsville in x years after 2010 is given by:

$y(x) > 2000x + 2100$

Will the population of Farmersville be greater than 6,300 in 2012?

2012 is 2012-2010 = 2 years after 2010, so we have to find y(2).

$y(2) > 2000(2) + 2100$

$y(2) > 6100$

The population can be greater than 6,100 but less than 6,300, and thus, we cannot determine if the population of Farmersville will be greater than 6,300 in 2012.

3 0

2 years ago