Answer:
The area of the shaded figure is:
Step-by-step explanation:
To obtain the area of the shaded figure, first, you must calculate this as a rectangle, with the measurements: wide (4 units), and long (6 units):
- Area of a rectangle = long * wide
- Area of a rectangle = 6 * 4
- Area of a rectangle = 24 units^2
How the figure isn't a rectangle, you must subtract the triangle on the top, so, now we calculate the area of that triangle with measurements: wide (4 units), and height (2 units):
- Area of a triangle =
- Area of a triangle =
- Area of a triangle =
- Area of a triangle = 4 units^2
In the end, you subtract the area of the triangle to the area of the rectangle, to obtain the area of the shaded figure:
- Area of the shaded figure = Area of the rectangle - Area of the triangle
- Area of the shaded figure = 24 units^2 - 4 units^2
- <u>Area of the shaded figure = 20 units^2</u>
I use the name "units" because the exercise doesn't say if they are feet, inches, or another, but you can replace this in case you need it.
1. 3x-6+2x+108+88=360
5x=170
x=34
2. figure B
The length is 4 yards longer than 3width so L = 3W+4
perimeter equal 408 yards
perimeter equal 2L +2W = 2(3W+4)+2W
408 = 6W +8 +2W
400=8W
W = 50
L = 3*50 +4 = 154
L = 154
W = 50
P = 2L +2W
408 = 2*50 +2*154
408 = 100 +308
408 = 408
hope that this is easy understandably
No local extrema i think?