We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
Given:
12cm to 2.5mm
To find:
The simplified for of given statement.
Solution:
We know that,
1 cm = 10 mm
12 cm =120mm
We have,
12cm to 2.5mm
It can be written as
Therefore, the value of 12 cm to 2.5 mm is 48 or 48:1.
Answer:
i dont get it
Step-by-step explanation:
Answer:
Two equiangular decagons are sometimes congruent.
39 inches i think, i’m sorry if i’m wrong
