step 1
Find out the slope WX
W(2,-3) and X(-4,9)
m=(9+3)/(-4-2)
m=12/-6
m=-2
step 2
Find out the slope YZ
Y(5,y) and Z(-1,1)
m=(1-y)/(-1-5)
m=(1-y)/-6
m=(y-1)/6
step 3
Remember that
If two lines are perpendicular
then
their slopes are negative reciprocal
that means
(y-1)/6=1/2 -----> because the negative reciprocal of -2 is 1/2
solve for y
2y-2=6
2y=6+2
2y=8
<h2>y=4</h2>
<h3>
Answer: Choice B</h3>
c^2-2cd+d^2 = (c-d)^2
We can verify this with the following steps
(c-d)^2 = (c-d)(c-d)
(c-d)^2 = c(c-d) - d(c-d)
(c-d)^2 = c^2-cd-cd+d^2
(c-d)^2 = c^2-2cd+d^2
Answer:
74.5°
Step-by-step explanation:
Hannah, the kite and Patricia form the vertices of a right-angled triangle with the hypotenuse side the length of the string L = 60 feet and adjacent side the distance between Hannah and Patricia = d = 16 feet.
Let the angle between the string and the sand be Ф.
By trigonometric ratios,
cosФ = adjacent/hypotenuse
= d/L
= 16 feet/60 feet
= 0.2667
Ф = cos⁻¹(0.2667)
= 74.53°
≅ 74.5°
So, he angle between the string and the sand is Ф = 74.5°
C. Because complementary angles are two angles whose sum equals 90 degrees so do 90-40=50 then 50x2= 100
Answer:
12
Step-by-step explanation:
64+52=118 studied in the cafeteria or lounge
but 20 studied in both, so 118-20 = 98 studied there in total
110 -98 = 12
