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2 years ago

5

The Sandhill School carnival sold $44 worth of advance tickets. The carnival organizers will also sell tickets at the door for $

4 each. If 67 people buy tickets at the door, what will the total ticket sales amount to?

1 answer:

ASHA 777 [7]2 years ago

5 0

Answer:

The total ticket sales amounts to $312

Step-by-step explanation:

67(4) + 44 = total sale

67(4) = 268

268 + 44 = 312

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George is 1.94 meters tall and wants to find the height of a tree in his yard. He started at the base of the tree and walked 10.

Free_Kalibri [48]

Draw a diagram to illustrate problem as shown below.

Let h = the height of the tree.

Because ΔABC ~ ΔADE, therefore
DE/BC = AD/AB

That is,
h/1.94 = (5.1 + 10.2)/5.1 = 3
h = 1.94*3 = 5.82 m

Answer: 5.82 m

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2 years ago

-54/-9 - (-5)= need help ASAP

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2 years ago

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A moving company’s moving rates can be represented by the function f(x) = 3x + 400, where x is the number of miles for the move.

Diano4ka-milaya [45]

Answer:

B) h(x) = –2x + 200

Step-by-step explanation:

f(x) = 3x + 400

g(x) = 5x + 200

f(x) - g(x) = 3x + 400 - (5x + 200) = -2x + 200

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2 years ago

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Someone please help!!

rewona [7]

Answer:

Option 2: (1,0) is the correct answer

Step-by-step explanation:

Given inequality is:

y>-5x+3

In order to find which point is solution to the given inequality we'll put the point one by one in the inequality. If the point satisfies the inequality, then the point is the solution of the inequality.

Putting (0,3) in inequality

$3 > -5(0)+3\\3>0+3\\3>3$

Putting (1,0) in inequality

$0>-5(1)+3\\0>-5+3\\0>-2$

Putting (-3,1) in inequality

$1 > -5(-3)+1\\1> 15+1\\1>16$

Putting (-1,-2) in inequality

$-2>-5(-1)+3\\-2>5+3\\-2>8$

The inequality is true for (1,0)

Hence,

Option 2: (1,0) is the correct answer

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2 years ago

What is the result of substituting for y in the bottom equation<br> y=x+3<br> y=x^2+2x-4

8_murik_8 [283]

The solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

<em><u>Solution:</u></em>

Given that,

$y = x + 3 ------- eqn 1\\\\y = x^2 + 2x - 4 ----- eqn 2$

<em><u>We have to substitute eqn 1 in eqn 2</u></em>

$x + 3 = x^2 + 2x - 4$

$\mathrm{Switch\:sides}\\\\x^2+2x-4=x+3\\\\\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}\\\\x^2+2x-4-3=x+3-3\\\\\mathrm{Simplify}\\\\x^2+2x-7=x\\\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\\\x^2+2x-7-x=x-x\\\\\mathrm{Simplify}\\\\x^2+x-7=0$

$\mathrm{Solve\:with\:the\:quadratic\:formula}\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=1,\:c=-7\\\\x =\frac{-1\pm \sqrt{1^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}$

$x = \frac{-1 \pm \sqrt{ 1 + 28}}{2}\\\\x = \frac{ -1 \pm \sqrt{29}}{2}$

$x = \frac{ -1 \pm 5.385 }{2}\\\\We\ have\ two\ solutions\\\\x = \frac{ -1 + 5.385 }{2}\\\\x = 2.1925$

$Also\\\\x = \frac{ -1 - 5.385 }{2}\\\\x = -3.1925$

Substitute x = 2.1925 in eqn 1

y = 2.1925 + 3

y = 5.1925

Substitute x = -3.1925 in eqn 1

y = -3.1925 + 3

y = -0.1925

Thus the solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

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2 years ago