Considering the whole progeny, there are 50% of probabilities of having a colorblind son. Considering only boys, there are 100% chances of having a colorblind son.
<h3>What is color blindness?</h3>
Color-blindness is a disfunction characterized by an alteration in color perception.
This alteration might affect perception from only partial confusion and difficulties in distinguishing some tones of green and red, up to no chromatic distinction.
Color-blindness is an X-linked condition.
- Women that are h0m0zyg0us recessive will be completely color-blinded (X⁺X⁺),
- Heter0zyg0us woman has partial color-blindness (X⁺X⁻).
- Men are or are not color-blinded (X⁺Y or X⁻Y).
<h3>Available data</h3>
- color-blindness is an X-linked recessive condition
- X⁻ represents the X chromosome carrying the color blindness allele.
- The allele for color blindness is recessive to the normal form of the gene, X ⁺.
⇒ If Samantha is color-blind, then her genotype is X⁻X⁻.
⇒ If Rick has normal vision, then his genotype is X⁺Y.
Cross: Samantha and Rick
Parentals) X⁻X⁻ x X⁺Y
Gametes) X⁻ X⁻ X⁺ Y
Punnett square) X⁻ X⁻
X⁺ X⁺X⁻ X⁺X⁻
Y X⁻Y X⁻Y
F1) 2/4 = 1/2 = 50% of the progeny is expected to be heter0zyg0us expressing partial-color blindness, X⁺X⁻.
2/4 = 1/2 = 50% of the progeny is expected to be completely color-blinded, X⁺Y.
100% of the girls are expected to be partial-color blinded, X⁺X⁻.
100% of the boys are expected to be color blinded, X⁻Y.
Answer: You can express your answer in two ways,
- 4/4 = 100% of probabilities of having a colorblind son (you are only considering boys in your answer).
- 1/2 = 50% of chances of having a colorblind son among the whole progeny (this answer includes girls as well).
You ca learn more about color-blindness at
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