Answer:
2) y = x - 4
y = -x + 2
=> x - 4 = -x + 2
=> 2x = -6
=> x = -3
=> y = -3 - 4 = -7
3) y = 3x + 1
y = 5x - 3
=> 3x + 1 = 5x - 3
=> 2x = 4
=> x = 2
=> y = 3(2) + 1 = 7
4) 2x + y = 8 => y = -2x + 8
y = x - 7
=> -2x + 8 = x - 7
=> 3x = 15
=> x = 5
=> y = 5 - 7 = -2
Explanation:
2)
y = x - 4
as they are equal:
-x + 2 = x - 4
-x - x = -4 - 2
-2x = -6
x = 3
y = -3 + 2
y = -1
solutions: (3,-1)
3)
y = 3x + 1
as y are equal:
5x - 3 = 3x + 1
5x - 3x = 1 + 3
2x = 4
x = 2
y = 3(2) + 1
y = 6 + 1
y = 7
solutions: (2,7)
4)
2x + y = 8
insert equation x - 7 in replace of y in equation 1
2x + x - 7 = 8
3x - 7 = 8
3x = 15
x = 5
y = 5 - 7
y = -2
solution's: (5,-2)
5
Step-by-step explanation:
The x is the domain and the y is the range. It's still a function