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Let's simplify step-by-step.
5x^3 + 3 + 2x^3 − x^2 + 1
= 5x^3 + 3 + 2x^3 + −x^2 + 1
Combine Like Terms:
= 5x^3 + 3 + 2x^3 + −x^2 + 1
= ( 5x^3 + 2x^3 ) + ( −x^2 ) + ( 3 + 1 )
= 7x^3 + −x^2 + 4
Answer:
= 7x^3 − x^2 + 4
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<u>Given</u><u> </u><u>info:</u><u>-</u>If the radius of a right circular cylinder is doubled and height becomes 1/4 of the original height.
Find the ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder ?
<u>Explanation</u><u>:</u><u>-</u>
Let the radius of the right circular cylinder be r units
Let the radius of the right circular cylinder be h units
Curved Surface Area of the original right circular cylinder = 2πrh sq.units ----(i)
If the radius of the right circular cylinder is doubled then the radius of the new cylinder = 2r units
The height of the new right circular cylinder
= (1/4)×h units
⇛ h/4 units
Curved Surface Area of the new cylinder
= 2π(2r)(h/4) sq.units
⇛ 4πrh/4 sq.units
⇛ πrh sq.units --------(ii)
The ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder
⇛ πrh : 2πrh
⇛ πrh / 2πrh
⇛ 1/2
⇛ 1:2
Therefore the ratio = 1:2
The ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder is 1:2
Answer:
(3a-7) (2a-1) is the answer
Step-by-step explanation:
Answer:
The second answer - 40, 10, 20, 50
Step-by-step explanation:
Range is the difference between the largest and smallest number in a data set. The biggest and smallest numbers in the data set are 50 and 10, respectively. 50 - 10 = 40.
62.50/5=12.50 for each tour
500/12.50 = 40 tours