1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).
2. Use formula to find the distance from point to the line Ax+By+C=0.
The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:
.
3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.
Answer: .
Answer:
10, 4, 8
Step-by-step explanation:
10 - 4 = 6
4 - 4 = 0
8 - 4 = 4
The correct answer is -9/22.
Answer:
no solution
Step-by-step explanation:
6x - 3y = 7 → (1)
- 2x + y = - 8 → (2)
multiplying (2) by 3 and adding to (1) eliminates the variables
- 6x + 3y = - 24 → (3)
add (1) and (3) term by term
0 + 0 = - 17
0 = - 17 ← false statement
This indicates the system has no solution