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1 year ago

(WILL GIVE BRAINLIST TO BEST ANSWER) What’s the missing angle based on the given angle measures.

Mathematics

2 answers:

matrenka [14]1 year ago

4 0

Answer:

∠3 = 107°

Step-by-step explanation:

Similar to the other question, ∠3 and ∠4 are supplementary and add up to 180 degrees as they make up the entirety of a straight line.

∠4 is 73°, so ∠3 has to be 107°.

Kaylis [27]1 year ago

3 0

Answer:

107°

Step-by-step explanation:

If you add up angle 3 and angle 4 you will get 180°

subtract 73 from 180

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zubka84 [21]

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2 years ago

F the value of x decreases by 6, how does the value of m(x + 9) change?

Yuki888 [10]

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Use the distributive property:

y= mx+9m

Now you want x to decrease by 6:

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y' = (mx+9m) - 6m

y' = y - 6m

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2 years ago

G find the area of the surface over the given region. use a computer algebra system to verify your results. the sphere r(u,v) =

Svetach [21]

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In calculus terms, we would first find an expression for the surface element, which is given by

$\displaystyle\iint_S\mathrm dS=\iint_S\left\|\frac{\partial\mathbf r}{\partial u}\times\frac{\partial\mathbf r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

$\dfrac{\partial\mathbf r}{\partial u}=a\cos u\cos v\,\mathbf i+a\cos u\sin v\,\mathbf j-a\sin u\,\mathbf k$
$\dfrac{\partial\mathbf r}{\partial v}=-a\sin u\sin v\,\mathbf i+a\sin u\cos v\,\mathbf j$
$\implies\dfrac{\partial\mathbf r}{\partial u}\times\dfrac{\partial\mathbf r}{\partial v}=a^2\sin^2u\cos v\,\mathbf i+a^2\sin^2u\sin v\,\mathbf j+a^2\sin u\cos u\,\mathbf k$
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So the area of the surface is

$\displaystyle\iint_S\mathrm dS=\int_{u=0}^{u=\pi}\int_{v=0}^{v=2\pi}a^2\sin u\,\mathrm dv\,\mathrm du=2\pi a^2\int_{u=0}^{u=\pi}\sin u$
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$=-2\pi a^2(-1-1)$
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as expected.

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2 years ago

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Xelga [282]

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