Answer:
disposal of radioactive waste
Explanation:
if too much is released, it can wipe out large parts of the country
A Cell with few energy needs would most likely contain a small number of Mitochondria.
- All cells require energy to function, but cells typically have significant energy needs that can only be met by the mitochondria, the cell's powerhouse.
- They transform glucose into ATP, a chemical with a huge energy storage capacity.
- Muscles have a large number of mitochondria, allowing them to react rapidly and powerfully to the body's ongoing need for energy.
- Macromolecules, defunct cell components, and microbes are all digested by lysosomes.
- Vacuoles are typically tiny and aid in the sequestration of waste.
- The ribosome, an intercellular structure consisting of both RNA and protein, is where a cell produces new proteins.
Therefore out of all these cell organelles, the cell has fewer mitochondria for less energy need.
Learn more about cell organelles here:
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Answer:
A. amount of precipitation, average temperature
Explanation:
Precipitation and average temperature are factors that climate includes. These factors are determined by other factors such as location of an area(like how far a place is from large bodies of water like the sea), ocean currents, lattitude (distance from the equator), winds (prevailing winds) , topography (such as mountains) and the like.
Answer:
[OH⁻] = 4.3 x 10⁻¹¹M in OH⁻ ions.
Explanation:
Assuming the source of the carbonate ion is from a Group IA carbonate salt (e.g.; Na₂CO₃), then 0.115M Na₂CO₃(aq) => 2(0.115)M Na⁺(aq) + 0.115M CO₃²⁻(aq). The 0.115M CO₃²⁻ then reacts with water to give 0.115M carbonic acid; H₂CO₃(aq) in equilibrium with H⁺(aq) and HCO₃⁻(aq) as the 1st ionization step.
Analysis:
H₂CO₃(aq) ⇄ H⁺(aq) + HCO₃⁻(aq); Ka(1) = 4.3 x 10⁻⁷
C(i) 0.115M 0 0
ΔC -x +x +x
C(eq) 0.115M - x x x
≅ 0.115M
Ka(1) = [H⁺(aq)][HCO₃⁻(aq)]/[H₂CO₃(aq)] = [(x)(x)/(0.115)]M = [x²/0.115]M
= 4.3 x 10⁻⁷ => x = [H⁺(aq)]₁ = SqrRt(4.3 x 10⁻⁷ · 0.115)M = 2.32 x 10⁻⁴M in H⁺ ions.
In general, it is assumed that all of the hydronium ion comes from the 1st ionization step as adding 10⁻¹¹ to 10⁻⁷ would be an insignificant change in H⁺ ion concentration. Therefore, using 2.32 x 10⁻⁴M in H⁺ ion concentration, the hydroxide ion concentration is then calculated from
[H⁺][OH⁻] = Kw => [OH⁻] = (1 x 10⁻¹⁴/2.32 x 10⁻⁴)M = 4.3 x 10⁻¹¹M in OH⁻ ions.
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NOTE: The 2.32 x 10⁻⁴M value for [H⁺] is reasonable for carbonic acid solution with pH ≅ 3.5 - 4.0.