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2 years ago

Equation for this slope

Mathematics

1 answer:

spin [16.1K]2 years ago

5 0

Answer:

m = y1 - y2/ x1 -x2

Step-by-step explanation:

Your coordinates are (4, 1) and (0, -3) so m (slope) equals 1 - (-3) over 4 - 0 = 4/4 = 1

Hope this helped!

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The sum of two numbers is 50 and their difference is 4 what are the two numbers

Deffense [45]

Answer:

27 and 23

Step-by-step explanation:

We can solve this problem as a system of equations. X is the first number and Y is the second number.

The first equation is x+y = 50 and the second equation is x-y=4

Now we solve the system, using elimination method:

x+y=50

x-y=4

2x = 54

x = 54/2

x = 27

And from any of the equations we can find Y

27 + y = 50

y = 50 - 27

y = 23

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2 years ago

Find the percent decrease. Round to the nearest percent. From 90°F to 70°F

Goryan [66]

Answer:

Step-by-step explanation:

90*x = 70

x = 7/9

x = 78%

100-78 = 22

3 0

2 years ago

Given cos t = 1/2 tan 0 find sin (t) and sec (t)

777dan777 [17]

Answer:

Sin(t) = $\frac{\sqrt{3} }{2} }$ and $sec(t) =2$

Step-by-step explanation:

The secant function is the reciprocal function of the cosine function. Therefore, given that $sec(t) = \frac{1}{cos(t)}$ then, if $cos(t) = \frac{1}{2}$ then $sec(t) =2$ .

On the other hand, if cos (t) = 1/2 ⇒ t = ± $\frac{\pi}{3}$

Then, the sin( $\frac{\pi}{3}$ ) = $\frac{\sqrt{3} }{2} }$

3 0

2 years ago

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Stels [109]

Answer:

Diameter = 43.96 $m^{2}$

Circumference = 153.86 $m^{2}$

8 0

2 years ago

2 tan 30° II 1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

2 years ago