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1 year ago

Which ordered pair is a solution to the linear inequality below

Mathematics

1 answer:

tensa zangetsu [6.8K]1 year ago

8 0

Answer:

Step-by-step explanation:

3(6)-5(-3)≥10

18-(-15)≥10

18+15≥10

33≥10

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The improper fraction 9/8 equals what mixed number

Lana71 [14]

The answers is 1 1/8

4 0

3 years ago

Write a function g whose graph represents a reflection in the y-axis followed by a translation 3 units to the right of the graph

svp [43]

Answer:

$g(x) = |x - 3|$

Step-by-step explanation:

Given

$f(x) = |x|$

Required

Translate 3 units right

The result of a right translated function is:

$g(x) = f(x - h)$

Where h is the unit of translation

$h = 3$

$g(x) = f(x - 3)$

Solve for f(x - 3)

$f(x) = |x|$

$f(x - 3) = |x - 3|$

Hence;

$g(x) = |x - 3|$

6 0

2 years ago

Simplify this expression 4X^2y^3 x 2x^3y^4

Lena [83]

Answer:

8^5^7

Step-by-step explanation:

Multiply the numbers:

4X^2 y^3 x 2x^3 y^4

8^2 ^3 ^3 ^4

Combine Exponents:

8^2 ^3 ^3 ^4

8^5 ^3 ^4

8^5 ^3 ^4

8^5 ^7

7 0

1 year ago

The weight of a box varies directly as the volume of the box. If a 138-pound box has a volume of 23 gallons, what is the weight

kolezko [41]

Answer:

D. 150 pounds

Step-by-step explanation:

For be directly proportional, it has to be that as one value increases the other does it equally, so

If 138 pound box has a volume of 23 gallons for 25 gallons ?. For being directly proportional tha value must be higest

138 → 23 $x=\frac{25*138}{23} = 150$

x → 25

5 0

2 years ago

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

2 years ago