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1 year ago

what is the suggested weight of the sample that should be disssolved in the beaker before it is transferred to the NMR tube

1 answer:

3 0

The sample must be sufficiently soluble (fig. 2) to yield an NMR spectrum. For 1H and 1H observed NMR, it is recommended to dissolve between 2 and 10 mg in between 0.6 and 1 mL of solvent so that the sample depth is at least 4.5 cm in the tube (fig. 3).

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Which causes genetic variations and can result in different alleles? O predation rate O random mutations O competition o environ

alekssr [168]

Answer:

Explanation:

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2 years ago

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luminum and oxygen react according to the following equation: 4Al(s) +3O2(g) --> 2Al2O3(s) What mass of Al2O3, in grams, can

Slav-nsk [51]

Answer: 8.7 grams

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{4.6g}{27g/mol}=0.17moles$

$4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)$

As oxygen is in excess, Aluminium is the limiting reagent and limits the formation of products.

According to stoichiometry:

4 moles of aluminium give = 2 moles of $Al_2O_3(s)$

Thus 0.17 moles of aluminium give= $\frac{2}{4}\times 0.17=0.085mol$

Mass of $Al_2O_3=moles\times {\text {molar mass}}=0.085\times 102g/mol=8.7g$

Thus the mass of $Al_2O_3(s)$ is 8.7 grams

8 0

2 years ago

Determine the molar solubility of pbso4 in pure water. ksp (pbso4) = 1.82 x 10-8.

Misha Larkins [42]

Use the ICE table approach as solution:

PbSO₄ --> Pb²⁺ + SO₄²⁻
I - 0 0
C - +s +s
E - s s

Ksp = [Pb²⁺][SO₄²⁻]
1.82×10⁻⁸ = s²
Solving for s,
s = <em>1.35×10⁻⁴ M</em>

5 0

2 years ago

Which of the following is a combustion reaction?

azamat

Answer:

A.NaOH+HCI+NaCI+H2O

Explanation:

It's a Acid-base

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2 years ago

What is 2.75 mol of O2

ANTONII [103]

Answer:

2,75 mol of O2 it's 88 g of O2.

Explanation:

The weight of the diatomic molecule O2 is 32 g/mol. So considering that, you should multiply 2,75 mol · 32 = 88g :)

3 0

2 years ago