#1
The uniforms are numbered 0, 1, 2, ..., 99. That's 100 numbers. Half of them are odd and half of them are even. So the probability that any one of the uniforms is odd is 1/2 just like the probability that any one uniform is even is 1/2.
(a) The numbers on the uniforms are independent of one another. That is, the number of her cross-country uniform does not in any way determine the number on her basketball uniform and vice versa. This means that we can find the probability that each is odd and multiply these together using what is called the counting principle. The probability that all are odd is:
(1/2)(1/2)(1/2)=1/8
(b) This is done the same way we did part (a). Since the probability of any one uniform being odd is the same as it being even (1/2), the answer here is the same: (1/2)(1/2)(1/2)=1/8
(c) This problem differs from that in (a) and (b). There is only one way for all three uniforms to be odd numbers: (odd, odd, odd) or all even (even, even, even). However, there are multiple ways for the uniforms to be two odd and one even. If the uniforms are listed in order: cross-country, basketball, softball we can get exactly one even in any of three ways:
even, odd, odd
odd, even, odd
odd, odd, even
The probability for any one of these possibilities is (1/2)(1/2)(1/2)=1/8 but since there are three way the probability that we get even exactly once is equal to (3)(1/8) = 3/8
Answer:
5q I would say
Step-by-step explanation:
As
3
x
−
q
=
5
q
, adding
=
q
on both sides, we get
3
x
−
q
+
q
=
5
q
+
q
or
3
x
=
6
q
, now multiplying both sides by
1
3
, we get
3
x
×
1
3
=
2
6
q
×
1
3
or
x
=
2
q
Answer:
(x+12)
Step-by-step explanation:
The middle number is 8 and the last number is -48.
Factoring means we want something like
(x+_)(x+_)
Which numbers go in the blanks?
We need two numbers that...
Add together to get 8
Multiply together to get -48
Can you think of the two numbers?
Try -4 and 12:
-4+12 = 8
-4*12 = -48
Fill in the blanks in
(x+_)(x+_)
with -4 and 12 to get...
(x-4)(x+12)
But, since (x-4) isn't an option, the answer would be (x+12)
Only cabinet with two silver coins is cabinet B.
The chance of choosing cabinet B is 1/3.
Thus, there is a 1/3 chance of the two cabinets contain 2 silver coins.
Answer:
I would say D.) is the best choice in this situation, The amount of female children you have does not determine the Gender that your child will be, The kids have nothing to do with the situation, The Father and Mother are what determine the Gender.
