Find the sum for:
(3x^2+4x−1)+(−2x^2−3x+2)=
1 answer:
Answer:
x^2+x+1
Step-by-step explanation:
(3x^2+4x−1)+(−2x^2−3x+2)
Combine like terms
3x^2-2x^2+4x-3x-1+2
x^2+x+1
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Step-by-step explanation: