I need the answer because i need to ask a question sry!
Given:
A right prism has height 7½ and triangular bases with sides of length 5, 12, and 13.
To find:
The total surface area of the prism.
Solution:
We have,
Height of prism = 7½ = 7.5
Sides of triangular base are 5, 12, 13. These sides of Pythagorean triplets because
So, the base of the prism is a right triangle.
Area of a triangle is
The area of the base is equal to the area of the top, i.e., sq units.
Perimeter of the base is
The curved surface area of the prism is
Now, the total area of the prism is
Therefore, the total surface area of the triangular prism is 285 square units.
Answer:
- 5/2
Step-by-step explanation:
Arrange this line equation into y = mx + b form m = slope
y = 2/5x + 12/5
then perpindicular line = - 1/m = - 1/ (2/5) = - 5/2
654 over 3 = divide the both 654 and 3 by 3.
It will give you 218 over 1.
So the answer is 218.
Step-by-step explanation:
L.H.S=(1-cosB)(1+cosB)
=(1-cos^2B). {using (a+b) (a-b)=(a^2-b^2)in second step}
=sin^2B
=1/cosec^2B
Therefore,L.H.S=R.H.S proved