What is the period of a wave that travels through a spring at 2.5 m/s and has a wavelength of 3m ?
1 answer:
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Answer:
Explanation:
f =
T = 120 N
L = 3.00 m
(m/L) = 120 g/cm(100 cm/m / 1000 g/kg) = 12 kg/m
(wow that's massive for a "rope")
f = )
f = /6 = 0.527 Hz
This is a completely silly exercise unless this "rope" is in space somewhere as the weight of the rope (353 N on earth) far exceeds the tension applied.
A much more reasonable linear density would be 120 g/m resulting in a frequency of √1000/6 = 5.27 Hz on a rope that weighs only 3.5 N
Explanation:
The given data is as follows.
= 0.8 kg/s = 800 g,
= 1 kg = 1000 g,
= (75 - T),
= T - 25
Now, according to the law of conservation of energy,
+ 30000
250.8 - 3.34T = 4.18T - 104.5 + 30
T =
=
Thus, we can conclude that temperature of the warm water stream is .