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1 year ago

If you are using Cosine and need to solve for an unknown hypotenuse, you should...

Mathematics

1 answer:

kifflom [539]1 year ago

6 0

Using cosine, we can find the hypotenuse by using the formula below;

hypotenuse = adjacent / cos ∅

<h3 /><h3 /><h3>Trigonometric ratios:</h3>

Trigonometric ratios are ratios of sides of a right angled triangle.
The simplest ratios are cosine, sine and tangent.

Using cosine, the hypotenuse side can be solved as follows:

cosine ∅ = adjacent / hypotenuse

cross multiply

hypotenuse cos ∅ = adjacent

divide both sides by cos ∅

hypotenuse cos ∅ / cos ∅ = adjacent / cos ∅

Therefore,

hypotenuse = adjacent / cos ∅

learn more on cosines here: brainly.com/question/10657732?referrer=searchResults

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In the circle below, which of the following equations for major arc GE is FALSE?

Helen [10]

Answer:

measure major arc GE = measure minor arc GC + measure minor arc FE

Step-by-step explanation:

All of the other options are applicable except for Option 1

=> Major Arc GE is not equal to Minor Arc GC + Minor Arc FE

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2 years ago

The 180 falls between which two whole numbers? A) 11 and 12 B) 12 and 13 C) 13 and 14 D) 14 and 15

Umnica [9.8K]

Answer:

C) 13 and 14

Step-by-step explanation:

To find the answer, we need to check for all the options.

A) 11 and 12 = 11 *12 = 132

B) 12 and 13 = 12 *13 = 156

C) 13 and 14 = 13*14 = 182

D) 14 and 15 = 14*15 = 210

In which, C) is true.

It is 182 which falls in 180's

Therefore, answer is C) 13 and 14

Hope this will helpful.

Thank you.

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2 years ago

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Answer:

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Answer:

$n_{tot}=44rev$

Step-by-step explanation:

In order to solve this problem we can make use of the following formula:

$\theta=(\frac{\omega_{f}+\omega_{0}}{2})t$

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Generally theta is written in radians and omega is written in radians per second. Now, since the revolutions are directly related to the radians and they want us to write our answer in revolutions, we can directly use the provided speeds in the formula, so we can rewrite it as:

$n=(\frac{f_{f}+f_{0}}{2})t$

where n represents the number of revolutions and f is the frequency at which the basket is turning.

The movement of the cylindrial basket can be split in two stages, when it accelerates and when it decelerates. So let's analye the first stage:

$n=(\frac{4rev/s+0}{2})(9s)=18rev$

and now let's analyze the second stage, where it decelerates, so we get:

$n=(\frac{0rev/s+4rev/s}{2})(13s)=26rev$

So now that we know how many revolutions the cylindrical basket will take as it accelerates and as it decelerates we can add them to get:

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