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1 year ago

PLEASE ANSWER BRAINLIEST

Mathematics

1 answer:

PIT_PIT [208]1 year ago

5 0

$24) \: m = \frac{ - 2- ( - 6)}{3 - 9} = \frac{ - 2}{3}$

$34) \: y = \frac{ - 3}{2} x + \frac{23}{2}$

Ok done. Thank to me :>

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With regard to mathematics, what is in excepted statement of fact that is used to prove other statements

ehidna [41]

Answer:

Axiom

Step-by-step explanation:

This is called a axiom. Not too sure if you mean the the definition but this is the definition. Hope this helped c:

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2 years ago

Value of x is 3.2x-9.6=38.4?

Svetradugi [14.3K]

Answer:

The steps that can be done to both sides of the equation is: Add 9.6, then divide by 3.2

Step-by-step explanation:

Solve the equation:

$3.2x - 9.6 = 38.4$

-First you add both sides 9.6:

$3.2x -9.6 +9.6 = 38.4 +9.6$

$3.2x = 48$

-Then, you divide both sides by 3.2:

$\frac{3.2x}{3.2} = \frac{48}{3.2}$

$x=15$

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2 years ago

Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real

hoa [83]

Answer: $0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8$

Step-by-step explanation:

We know that the standard quadratic equation is ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

$b^2-4ac=(-7)^2-4(2)(-9)=49+72>0$

So it has 2 real number solutions.

2. a=1, b=-4, c=4

$b^2-4ac=(-4)^2-4(1)(4)=16-16=0$

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

$b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0$

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

$b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0$

So it has 2 real number solutions.

5. a=3, b=5, c=3

$b^2-4ac=(5)^2-4(3)(3)=25-36=-9$

Thus it does not has real solutions.

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