p(x)= x-2
g(x)= 2x^3 + 3x^2 - 11x - 6
first we have to find the zero of the polynomial of x-2
p(x)= x-2 = 0
x=2
therefore,
p(x)= 2x^3 + 3x^2 - 11x - 6
p(2)= 2*2^3 + 3*2^2 - 11*2 - 6
= 2*8 + 3*4 - 11*2 - 6
= 16 + 12 - 22 - 6
= 28-28
= 0
Hope it helped u, ^_^.
Answer:
0.8*x*(‑5)/7
Step-by-step explanation:on the qraph
Answer:
if u ll v then this angel is the twin of the one below and is 180-72
Step-by-step explanation:
Answer:
<u>The track consumes ≅ 61 liters of fuel every 100 kilometres</u>
Step-by-step explanation:
As we can see in the graph, the total distance that the truck can travel with 500 liters of fuel is ≅ 825 kilometres.
For answering the question properly, we use the Rule of Three Simple, this way:
Kilometres Liters of fuel
825 500
100 x
Solving for x, we have:
825 * x = 500 * 100
825x = 50,000
x = 50,000/825
x = 60.6 liters of fuel (61 rounding to the next whole)
x ≅ 61 liters of fuel
<u>The track consumes ≅ 61 liters of fuel every 100 kilometres</u>
It would be 6x + 6y as the final expansion
