In mathematical analysis, Clairaut's equation is a differential equation of the form where f is continuously differentiable. It is a particular case of the Lagrange differential equation
Answer:
r = - 7, r = - 5
Step-by-step explanation:
Given
r² = - 12r - 35 ( add 12r to both sides )
r² + 12r = - 35
To complete the square
add ( half the coefficient of the r- term )² to both sides
r² + 2(6)r + 36 = - 35 + 36
(r + 6)² = 1 ← take the square root of both sides )
r + 6 = ± 1 ( subtract 6 from both sides )
r = - 6 ± 1, thus
r = - 6 - 1 = - 7 or r = - 6 + 1 = - 5
<em>See</em><em> </em><em>above</em><em> </em><em>explanation</em>
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3 + 1.75m
This represents 1.75 per mile plus a one time 3 charge.
Another way this can be written is
(1.75m + 6) - 3
This is a less efficient way, but represents the same. It is 1.75 per mile, this is plus 6, therefore we add the -3 outside the parenthesis so it evens out to +3 as the base charge.
Example: Lets say its 3 miles.
3 + 1.75 (3) = 8.25
(1.75 (3) + 6) - 3 = 8.25
