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1 year ago

Solve the equation. Graph the solution(s) if possible. ∣x−3∣+4=9

Mathematics

1 answer:

Mazyrski [523]1 year ago

3 0

Answer:

x=8

x=-2

Step-by-step explanation:

∣x−3∣+4=9

= ∣x−3∣=5

Positive term: (x-3)

(x-3) = 5

Rearrange and Add up

x = 8

Negative term: -(x-3)

Multiply

-x+3 = 5

Rearrange and Add up

-x = 2

Multiply both sides by (-1)

x = -2

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Savatey [412]

Answer:

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8 0

1 year ago

Read 2 more answers

Solve for t 64= -8(t+85)

erastova [34]

Answer: t = -93

Step-by-step explanation:

64= -8(t+85)

64= -8t - 680

744= -8t

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4 0

2 years ago

Which ordered pair is a solution to the system of linear equations 1/2x-3/4y=11/60 and 2/5x+1/6y=3/10

natka813 [3]

ANSWER

$( \frac{2}{3} , \frac{1}{5} )$

EXPLANATION

The first equation is

$\frac{1}{2} x - \frac{3}{4} y = \frac{11}{60} ...(1)$

The second equation is

$\frac{2}{5} x + \frac{1}{6} y = \frac{3}{10} ...(2)$

We want to eliminate y, so we multiply the first equation by

$\frac{4}{5}$

$\frac{4}{5} \times \frac{1}{2} x - \frac{4}{5} \times \frac{3}{4} y = \frac{11}{60} \times \frac{4}{5}$

$\frac{2}{5} x - \frac{3}{5} y = \frac{11}{75} ...(3)$

We now subtract equation (3) from (2)

$(\frac{2}{3} x - \frac{2}{3} x )+ ( \frac{1}{6} y - - \frac{3}{5}y ) =( \frac{3}{10} - \frac{11}{75} )$

$\frac{1}{6} y + \frac{3}{5}y =\frac{3}{10} - \frac{11}{75}$

$\frac{23}{30}y = \frac{23}{150}$

Multiply both sides by

$\frac{30}{23}$

$\implies \: \frac{30}{23} \times \frac{23}{30}y= \frac{23}{150} \times \frac{30}{23}$

$\implies \: y = \frac{1}{5}$

Substitute into the first equation to solve for x .

$\frac{1}{2} x - \frac{3}{4} \times \frac{1}{5} = \frac{11}{60}$

Multiply to obtain

$\frac{1}{2} x - \frac{3}{20} = \frac{11}{60}$

$\frac{1}{2} x = \frac{11}{60} + \frac{3}{20}$

$\frac{1}{2} x = \frac{1}{3}$

Multiply both sides by 2.

$2 \times \frac{1}{2} x =2 \times \frac{1}{3}$

$x = \frac{2}{3}$

The solution is

$( \frac{2}{3} , \frac{1}{5} )$

5 0

2 years ago

Read 2 more answers

I got this far in my working out and am already stuck. have i gone wrong?

Kipish [7]

Yes, you made an algebraic error. By multiplying 18 x 4, you messed up on order of operations.

(x+9)(x+2)*4

becomes:

(x^2+11x+18)*4

= 4x^2 + 44x + 72

anyway, this is how I would do this problem:

(x+9)(x+2)(4) = 912

(x+9)(x+2) = 228

x^2 + 11x + 18 = 228

x^2 + 11x - 220 = 0

(x+21)(x-10) = 0

x = -21 or 10

The dimensions can't be negative, so we only use x = 10

The dimensions are then 10+9, 10+2, 4

or 19, 12, 4

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2 years ago

Ericka and her friend are going to reshelf library books. Sherri will reshelf 50% and Ericka will reshelf 2/5 of the books. If t

ipn [44]

Ok so we start with 80 books and remove 50% so 40
2/5 of 40 is 16
16 books

5 0

2 years ago