Answer:
It will be reported too low.
Explanation:
To measure the specific heat of the metal (s), the calorimeter may be used. In it, the metal will exchange heat with the water, and they will reach thermal equilibrium. Because it can be considered an isolated system (there're aren't dissipations) the total amount of heat (lost by metal + gained by water) must be 0.
Qmetal + Qwater = 0
Qmetal = -Qwater
The heat is the mass multiplied by the specific heat multiplied by the temperature change. If c is the specific heat of the water:
m_metal*s*ΔT_metal = - m_water *c*ΔT_water
s = -m_water *c*ΔT_water / m_metal*ΔT_metal
So, if m_water is now less than it was supposed to be, s will be reported too low, because they are directly proportional.
Answer:
Radiation
Explanation:
A sun transfers energy by radiation. However, there are three different modes of heat energy transfer -
a) Radiation
b) Conduction
c) Convection
Since sun is a at a very far distance from earth, it cannot transfer its heat energy by conduction as for this mode of heat transfer two bodies need to be in touch with each other.
For convection mode of heat transfer a medium is required but for transfer of sun's energy (which is electromagnetic radiation) no medium is required.
Hence, Sun will transfer energy by radiation only.
Hope This Helps!!! <3
The answer is c. because you have to increase concentration of h2
