Answer:
16 questions right = 80%
So Peter missed 4 questions.
Hope this helps.
:-)
Whats the normal arm span for these heights? : 4'10,4'11,5'0,5'4,5'5,5,'7,5'8,5'9,5'10,5'11,6'0
Svetllana [295]
In adults, the arm span is approximately 5 cm greater than the height in adult males and 1.2 cm in
adult females. To calculate the arm span for the heights given, we add
5cm to their height. The following are the results:
Height Arm Span Length (in cm)
4’10 152.32
4’11 154.86
5’0 157.4
5’4 167.56
5’5 170.10
5’7 175.18
5’8 177.72
5’9 180.26
5’10 182.80
5’11 185.34
6’0 187.88
To add, the total measurement of the length from the furthermost
part of an individual's arms to the other end
when raised equidistant to the ground at shoulder height at a 90º angle
is called the arm span or wingspan.
Answer:
1/-4
Step-by-step explanation:
(2,-3),(-2,-2)
-2 + 3/ -2 - 2
1/-4
Answer:
4356.020
Step-by-step explanation:
Answer:
V(max) = 8712.07 in³
Dimensions:
x (side of the square base) = 16.33 in
girth = 65.32 in
height = 32.67 in
Step-by-step explanation:
Let
x = side of the square base
h = the height of the postal
Then according to problem statement we have:
girth = 4*x (perimeter of the base)
and
4* x + h = 98 (at the most) so h = 98 - 4x (1)
Then
V = x²*h
V = x²* ( 98 - 4x)
V(x) = 98*x² - 4x³
Taking dervatives (both menbers of the equation we have:
V´(x) = 196 x - 12 x² ⇒ V´(x) = 0
196x - 12x² = 0 first root of the equation x = 0
Then 196 -12x = 0 12x = 196 x = 196/12
x = 16,33 in ⇒ girth = 4 * (16.33) ⇒ girth = 65.32 in
and from equation (1)
y = 98 - 4x ⇒ y = 98 -4 (16,33)
y = 32.67 in
and maximun volume of a carton V is
V(max) = (16,33)²* 32,67
V(max) = 8712.07 in³