If I am understanding this right, since the <em>c </em>is a variable, you'd have to solve the equation and have the variable in the and result.
the sqrt525^7 = 3359983566.19
So you'd have to simplify this and add the <em>c</em> to the end of it. Unless your work is fractions.
(I take Algebra II I should be more confident on this topic, this is just what makes the most sense)
Answer:
the first one is
+2 +4 + 8 + 16 +32
he multiply by 2 every time he add numbers so its 65
the second one he make this
-8 -4 -2 -1
every time he Take from numbers he devide by 2
so its 5
the third one
+6 +18 + 54 + 162
every time he add he multiply by 3
ao its 162 +80 =242
the fourth one is
+33 +66 + 132 +264
he multiply by 2 every time he add
so its 267+264=531
the fiveth one is
he put the roots
2²,3²,4²,5²,6²
so the answer is 36
Step-by-step explanation:
A 65
B 5
C 242
D 531
E 36
hopefully its helpful man
Answer:
RP: x equals 0
JH: x equals -11
EG: x equals 9
Answer:
6
Step-by-step explanation:
(8/3) / (-4/9)
when dividing fractions you use the acronym k.c.f (keep change flip)
keep the first fraction
change the operation (divide to multiply)
flip the other fraction
(8/-3) x (9/4)
after re-writing your expression, you want to solve
do this by multiplying both numerators by each other and same with the denominators
(-8x9) / (3x-4)
then you get a new fraction,
-72/-12
simplify,
-72/-12 = 6 (multiplying/dividing 2 negatives will always give you a positive)