Answer: Word problem: Mya goes to a carnival and buys food for her and her friends. She buys 5 funnel cakes that were $20 each. She buys 10 buckets of popcorn that were 8 dollars each.

Regular problem: $20+$15+$20+$100+$25=180

Step-by-step explanation: I didn't know what you needed. I'm sorry if that's not it, but hope it helps.

7 0

2 years ago

I really need help with this and how you got it please 10 points!!

Kamila [148]

Answer:

1 and 7 are congruent

2 and 5 are supplementary

4 and 6 are congruent

3 and 8 are supplementary

8 0

2 years ago

The graph shows the cost of buying beets at a farm stand

antiseptic1488 [7]

Answer:

Ok what's your question? cna you include the graph?

8 0

2 years ago

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

kozerog [31]

Answer: 49.85%

Step-by-step explanation:

Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.

i.e. $\mu=61$ and $\sigma=9$

To find : The approximate percentage of lightbulb replacement requests numbering between 34 and 61.

i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and $34+3(9)$ .

i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between $\mu$ and $\mu+3(\sigma)$ . (1)

According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.

i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.

i.e.,The approximate percentage of lightbulb replacement requests numbering between $\mu$ and $\mu+3(\sigma)$ = 49.85%

⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%

4 0

2 years ago