Answer:
D: 57 + 30x = 150
Step-by-step explanation:
63-3(2-10x)=150
63 - 6 + 30x = 150
57 + 30x = 150
Margin of error, e = Z*SD/Sqrt (N), where N = Sample population
Assuming a 95% confidence interval and substituting all the values;
At 95% confidence, Z = 1.96
Therefore,
0.23 = 1.96*1.9/Sqrt (N)
Sqrt (N) = 1.96*1.9/0.23
N = (1.96*1.9/0.23)^2 = 262.16 ≈ 263
Minimum sample size required is 263 students.
Answer: p = −15
Step-by-step explanation:
Add 11p to both sides.
−10p+11p=−11p−15+11p
p=−15
(17-7)*2=weekly allowance
so her weekly allowance is 20
Answer:
I'm not sure, but it might be 120.