Answer: segment KH
Explanation:
The altitude of a triangle is defined as a segment connecting one of the vertex of the triangle with the opposite side of the triangle (or with an external prolongation of it), forming a right angle with it.
Note that the altitude of a triangle can also be outside the area of the triangle.
If we look at the picture, we see that:
- IH is a side, so it is not an altitude of the triangle
- KH is an altitude of the triangle, since it connects the vertex H with the external prolongation of IG, and it makes a right angle with it
- GJ: we don't know if it is an altitude, since we don't know if it forms a right angle or not
- GH: it is a side of the triangle, so it is not an altitude
So, the correct answer is segment KH.
Is it 4x squared? if so the answer would be A
Vertex at the origin and opening down → y=ax^2
Width: w=16
x=w/2→x=16/2→x=8
x=8, y=-16→y=ax^2→-16=a(8)^2→-16=a(64)→-16/64=a(64)/64→-1/4=a→a=-1/4
y=ax^2→y=-(1/4)x^2
7 m from the edge of the tunnel → x=w/2-7=8 m-7 m→x=1 m
x=1→y=-(1/4)x^2=-(1/4)(1)^2=-(1/4)(1)→y=-1/4
Vertical clearance: 16-1/4=16-0.25→Vertical clearance=15.75 m
Please, see the attached file.
Answer: Third option 15.75 m